21xrx.com
2024-06-03 10:12:20 Monday
登录
文章检索 我的文章 写文章
C++双人贪吃蛇代码
2023-07-05 11:29:51 深夜i     --     --
C++ 双人 贪吃蛇 代码

贪吃蛇是一款经典的游戏，不仅深受小朋友的喜欢，也在程序员中广受欢迎。C++作为一种广泛应用于计算机科学领域的编程语言，自然也非常适合编写贪吃蛇游戏。下面将介绍一份C++双人贪吃蛇代码示例。

在编写该代码之前，我们需要先明确游戏的规则。贪吃蛇游戏中，玩家需要操控蛇前进，并尽可能多地吃到食物。每吃到一个食物，蛇的长度就会增加，同时游戏难度也会随之提高。如果蛇头撞到了游戏边界或自己的身体，那么游戏就会结束。

C++双人贪吃蛇代码示例：



#include <iostream>


#include <conio.h>


#include <windows.h>


using namespace std;


bool gameOver;


const int width = 20;


const int height = 20;


int x1, y1, x2, y2, fruitX, fruitY, score1, score2;


int tailX[100], tailY[100];


int nTail1=0, nTail2=0;


enum eDirection RIGHT;


eDirection dir1, dir2;


void Setup()


{


  gameOver = false;


  dir1 = STOP;


  dir2 = STOP;


  x1 = width / 4;


  y1 = height / 2;


  x2 = 3 * width / 4;


  y2 = height / 2;


  fruitX = rand() % width;


  fruitY = rand() % height;


  score1 = 0;


  score2 = 0;


}


void Draw()


{


  system("cls"); //清屏


  for (int i = 0; i < width+2; i++)


    cout << "#";


  cout << endl;


  for (int i = 0; i < height; i++)


  {


    for (int j = 0; j < width; j++)


    {


      if (j == 0)


        cout << "#";


      if (i == y1 && j == x1)


        cout << "A";


      else if (i == y2 && j == x2)


        cout << "B";


      else if (i == fruitY && j == fruitX)


        cout << "F";


      else


      {


        bool print = false;


        for (int k = 0; k < nTail1; k++)


        {


          if (tailX[k] == j && tailY[k] == i)


          


            print = true;


            cout << "a";


          


        }


        for (int k = 0; k < nTail2; k++)


        {


          if (tailX[k] == j && tailY[k] == i)


          


            print = true;


            cout << "b";


          


        }


        if (!print)


          cout << " ";


      }


      if (j == width - 1)


        cout << "#";


    }


    cout << endl;


  }


  for (int i = 0; i < width+2; i++)


    cout << "#";


  cout << endl;


}


void Input1()


{


  if (_kbhit()) //如果有输入


  {


    switch (_getch()) //获取输入


    


    case 'a':


      dir1 = LEFT;


      break;


    case 'd':


      dir1 = RIGHT;


      break;


    case 'w':


      dir1 = UP;


      break;


    case 's':


      dir1 = DOWN;


      break;


    case 'x':


      gameOver = true;


      break;


    


  }


}


void Input2()


{


  if (_kbhit()) //如果有输入


  {


    switch (_getch()) //获取输入


    


    case 'j':


      dir2 = LEFT;


      break;


    case 'l':


      dir2 = RIGHT;


      break;


    case 'i':


      dir2 = UP;


      break;


    case 'k':


      dir2 = DOWN;


      break;


    case 'm':


      gameOver = true;


      break;


    


  }


}


void Logic()


{


  int prevX1 = tailX[0];


  int prevY1 = tailY[0];


  int prevX2 = tailX[0];


  int prevY2 = tailY[0];


  int prev2X, prev2Y;


  tailX[0] = x1;


  tailY[0] = y1;


  for (int i = 1; i < nTail1; i++)


  {


    prev2X = tailX[i];


    prev2Y = tailY[i];


    tailX[i] = prevX1;


    tailY[i] = prevY1;


    prevX1 = prev2X;


    prevY1 = prev2Y;


  }


  int prev2X2, prev2Y2;


  tailX[0] = x2;


  tailY[0] = y2;


  for (int i = 1; i < nTail2; i++)


  {


    prev2X2 = tailX[i];


    prev2Y2 = tailY[i];


    tailX[i] = prevX2;


    tailY[i] = prevY2;


    prevX2 = prev2X2;


    prevY2 = prev2Y2;


  }


  switch (dir1)


  {


  case LEFT:


    x1--;


    break;


  case RIGHT:


    x1++;


    break;


  case UP:


    y1--;


    break;


  case DOWN:


    y1++;


    break;


  default:


    break;


  }


  if (x1 >= width)


    x1 = 0;


  else if (x1 < 0)


    x1 = width - 1;


  if (y1 >= height)


    y1 = 0;


  else if (y1 < 0)


    y1 = height - 1;


  if (x1 == fruitX && y1 == fruitY)


  {


    score1 += 10;


    fruitX = rand() % width;


    fruitY = rand() % height;


    nTail1++;


  }


  for (int i = 0; i < nTail1; i++)


    if (tailX[i] == x1 && tailY[i] == y1)


      gameOver = true;


  switch (dir2)


  {


  case LEFT:


    x2--;


    break;


  case RIGHT:


    x2++;


    break;


  case UP:


    y2--;


    break;


  case DOWN:


    y2++;


    break;


  default:


    break;


  }


  if (x2 >= width)


    x2 = 0;


  else if (x2 < 0)


    x2 = width - 1;


  if (y2 >= height)


    y2 = 0;


  else if (y2 < 0)


    y2 = height - 1;


  if (x2 == fruitX && y2 == fruitY)


  {


    score2 += 10;


    fruitX = rand() % width;


    fruitY = rand() % height;


    nTail2++;


  }


  for (int i = 0; i < nTail2; i++)


    if (tailY[i] == y2 && tailX[i] == x2)


      gameOver = true;


}


void Print()


{


  cout << "Player A Score:" << score1 << endl;


  cout << "Player B Score:" << score2 << endl;


  if (gameOver)


    cout << "Game Over!" << endl;


}


int main()


{


  Setup();


  while (!gameOver)


  {


    Draw();


    Input1();


    Input2();


    Logic();


    Print();


    Sleep(100);


  }


  return 0;


}

该代码实现了基本的双人贪吃蛇游戏，其中通过枚举类型eDirection定义了蛇前进的方向。在Setup()函数中初始化游戏，Draw()函数负责绘制游戏界面，Input1()和Input2()函数分别处理两个玩家的输入。Logic()函数处理游戏逻辑，Print()函数输出游戏的得分和结束信息。

在运行该代码时，我们需要先将conio.h和windows.h头文件引入，否则会编译错误。同时，代码中使用了_kbhit()和_getch()函数来获取玩家的输入。_kbhit()函数用于判断是否有输入，_getch()函数用于获取输入的字符。

以上是一份简单的C++双人贪吃蛇代码示例，希望对初学者学习C++语言有所帮助。

  
  

评论区

{{item['qq_nickname']}}
()
回复
回复